9^x=(1/27)^x+2

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Solution for 9^x=(1/27)^x+2 equation: 



9^x=(1/27)^x+2

We move all terms to the left:

9^x-((1/27)^x+2)=0



Domain of the equation: 27)^x+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

9^x-((+1/27)^x+2)=0

We multiply all the terms by the denominator


9^x*27)^x+2)-((+1=0

Wy multiply elements

243x^2+1=0

a = 243; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·243·1
Δ = -972
Delta is less than zero, so there is no solution for the equation

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